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3.14x^2-11.2x+0.5=0
a = 3.14; b = -11.2; c = +0.5;
Δ = b2-4ac
Δ = -11.22-4·3.14·0.5
Δ = 119.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.2)-\sqrt{119.16}}{2*3.14}=\frac{11.2-\sqrt{119.16}}{6.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.2)+\sqrt{119.16}}{2*3.14}=\frac{11.2+\sqrt{119.16}}{6.28} $
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